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0.7x-14x^2=0
a = -14; b = 0.7; c = 0;
Δ = b2-4ac
Δ = 0.72-4·(-14)·0
Δ = 0.49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0.7)-\sqrt{0.49}}{2*-14}=\frac{-0.7-\sqrt{0.49}}{-28} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0.7)+\sqrt{0.49}}{2*-14}=\frac{-0.7+\sqrt{0.49}}{-28} $
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